Sed match any number of spaces
Web26 May 2005 · Remove the first word on each line (including any leading spaces and the trailing space): cat test3.txt sed -e 's/^ * [^ ]* //' More regular expression matching is used in this example. Here's what it is doing. The initial ^ * is used to match any number of spaces at the beginning of the line. Web1 Answer Sorted by: 7 You should use the g (global) flag, which makes sed act on all matches of the pattern on each line, rather than the first match on each line: sed 's/ //g' test.txt > test2.txt Share Improve this answer Follow edited Oct 19, 2014 at 17:40 evilsoup 12.9k 2 59 80 answered Jul 25, 2010 at 10:31 jmz 186 2 Excellent!
Sed match any number of spaces
Did you know?
WebUse sed -e "s/ [ [:space:]]\+/ /g" Here's an explanation: [ # start of character class [:space:] # The POSIX character class for whitespace characters. It's # functionally identical to [ \t\r\n\v\f] which matches a space, # tab, carriage return, newline, vertical tab, or form feed. WebUsing a tab (see # note on '\t' at end of file) instead of space will preserve margins. sed = filename sed 'N;s/\n/\t/' # number each line of a file (number on left, right-aligned) sed = …
Websed example from 3. sed example from 3/9 lecture. adapted from Do It With Sed. In lecture on Friday, I showed the following sed script to take a text file and center every line (assuming lines have 80 columns): #!/usr/bin/sed -f # center all lines of a file, on a 80 columns width # to change that width, the number in \ {\} must be replaced, and ... Web1 Apr 2013 · GNU sed does support the \s – but it'd be more portable to simply add the space to your regular expression. Finally, your . matches one character, so your regex …
Websed -E 's/ (native_transport_port:\s)9042/\19080/' which re-uses the matched text in the replacement. If your sed doesn't support Perl-style \s, you can match on space instead: …
WebWhen I use sed to replace all the spaces with X, the command works, the command being: sed 's/ /X/g' filelist.tmp However, when I try the same to replace all occurrences of space …
Web16 Apr 2024 · However, if we include two spaces in the search pattern, sed must find at least one space character before it applies the substitution. This ensures nonspace characters will remain untouched. We type the following, using the -e (expression) we used earlier, which allows us to make two or more substitutions simultaneously: disk check command windows 11Web25 Sep 2024 · 3 Answers Sorted by: 6 One fairly straightforward approach would be to replace the first "hash" by "hash space" only in lines that begin with "hash not space": $ echo "#ok" sed "/^# [^ ]/s # # " # ok In regex variants that provide it, like Perl, you could use negative lookahead: $ echo "#ok" perl -pe 's/^# (?! )/# /' # ok Share disk check command cmdWeb24 Sep 2024 · 3 Answers Sorted by: 6 One fairly straightforward approach would be to replace the first "hash" by "hash space" only in lines that begin with "hash not space": $ … disk check could not be performed becauseWeb6 Nov 2024 · sed maintains two data buffers: the active pattern space, and the auxiliary hold space. Both are initially empty. sed operates by performing the following cycle on each line of input: first, sed reads one line from the input stream, removes any trailing newline, and places it in the pattern space. cowboys 2 board game bggWebMatches the null string at beginning of the pattern space, i.e. what appears after the circumflex must appear at the beginning of the pattern space. In most scripts, pattern space is initialized to the content of each line (see How sedworks). So, it is a useful simplification to think of ^#includeas matching only cowboys 2023 nfl mock draft 7 roundsWebAll 4 combinations are possible. There is support in sed for both obsolete and extended, but in either case only for non-enhanced. The \d operator is a feature of enhanced regular … disk check command lineWeb29 Jan 2016 · This should match: sed 's/ [a-z] [ ]* [a-z] [ ]* [0-9]*//gi'. Your 1st try misses a couple of square brackets, and you don't need the outermost one: sed 's/ [a-z] [ [:space:]] [a … disk chain is consistent